Answer to Question #166839 in Physical Chemistry for alex

Question

how many liters of oxygen are needed to react when 8.23 x 10^26 molecules of water are produced at stp?

Answer 1

At STP, one mole of any gas occupies a volume of 22.4 L.

Thus 3.36 L of oxygen (O2) gas correspond to:

Moles of oxygen = 3.36 L × (1 mol / 22.4 L) = 0.15 mol

Moles of oxygen = 0.15 mol

One mole of any substance contains 6.022×10²³ atoms/molecules.

Hence,

Oxygen molecules = (0.15 mol of oxygen) × (6.022×10²³ molecules / 1 mol) = 9.033×10²² O₂ molecules

Oxygen molecules = 9.033×10²² O₂ molecules