Answer to Question #150081 in Physical Chemistry for Dayton North

Question #150081

How many moles of gas does it take to occupy 120 liters at a pressure of 2.3 atmospheres and a temperature of 340 K?

Expert's answer

pV=nRT

p = 2.3 atm = 202650 Pa

V = 120 l = 0.12 m³

T = 340 K

n = pV/(RT) = 202650*0.12/(8.314*340) = 8.60 mol

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