2Al + 6HCl = 2AlCl3 + 3H2
M (Al) = 26.98 g/mol
2 x 26.98 reacts
M (HCl) = 36.46 g/mol
6 x 36.46 g reacts
Given mass of Al: 1.87 g
The ratio is:
1.87 / 2x26.98 = x / 6x36.46
x = 7.58 g of HCl
The mass of the solution:
7.58 / 0.28 = 27.08 g
d = m/V
V = m/d
V = 27.08 / 1.14 = 23.75 mL
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