Question #144333
how many molecules is 415 L sulfur dioxide a STP
1
Expert's answer
2020-11-14T14:00:35-0500

At STP, 1 mole of any gas occupies 22.4 L.

Therefore,

nSO2=415L22.4L/mol=18.5moln_{SO_2}=\frac{415L}{22.4L/mol}=18.5mol


Number of molecules equals 18.5mol×6.0221023=1.11102518.5mol\times6.022\cdot10^{23}=1.11\cdot10^{25}


Answer: 1.1110251.11\cdot10^{25}


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