+40.7 kJ mol-1 is same as per 18.02 g of water
We have 1000 g (1 kg)
Simple math gives us:
40.7 x 1000 / 18.02 = 2258.6 kJ
of energy needed to evaporate water
3 kW = 3 kJ / s or
3 kJ of energy is used per 1 second
2258.6 / 3 = 752.87 s or 12.5 min
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