Question

0.45g of a dibasic acid is completely neutralized with 100ml N/10 NaOH. The molecular weight of acid is

Answer 1

Solution.

$H2X + 2NaOH = 2NaX + 2H2O$

$N(NaOH) = \frac{1}{10} = 0.1 N$

$n(NaOH) = 0.1 \times 0.1 = 0.01 mol$

$n(H2X) = \frac{n(NaOH)}{2}$

n(H2X) = 0.005 mol

$M(H2X) = \frac{m(H2X)}{n(H2X)} = 90 g/mol$

Answer:

90 g/mol