Answer to Question #138407 in Physical Chemistry for Aashuu

Question

In a second order reaction 2A is converted into products, the final concentration is .28M. What is the initial concentration if k=.32M-1 s -1 and the time is 5 seconds.

Answer 1

k=0.32M-1 s -1

time ,t = 5 sec

final concentration, A= 0.28M

 2A--> products 

for 2nd order , integrated rate law is given

1/A0 = 1/A -Kt 

plug in above numbers

1/A0 = 1/0.28 M - 0.32M-1 s -1 * 5 s

  1/A0 = 1.971428 M-1

A0 = 0.507 M

ANSWER

Final concentration = 0.507 M