Question #115487

How are spherical polar coordinates related to the rectangular cartesian coordinates? Illustrate
giving suitable relations. Also write the Schrodinger equation for hydrogen atom in spherical polar coordinates

Expert's answer

Answer:

The spherical polar coordinates rr, θ\theta and ϕ\phi are related to Cartesian coordinates xx, yy and zz via the following equations:

x=r sinθ cosϕx = r\text{ sin} \theta\text{ cos} \phi

y=r sinθ sinϕy = r\text{ sin} \theta\text{ sin}\phi

z=r cosθz = r \text{ cos}\theta .

And vice versa:

r=x2+y2+z2r = \sqrt{x^2+y^2+z^2}

ϕ=arctanyx\phi = \text{arctan} \frac{y}{x}

θ=arctanx2+y2z\theta =\text{arctan}\frac{\sqrt{x^2+y^2}}{z} .

The time-independent Schrödinger equation in spherical polar coordinates for hydrogen atom is:

{22μr2[r(r2r)+1sinθθ(sinθθ)+1sin2θ2ϕ2]e24πϵ0r}ψ(r,θ,ϕ)=Eψ(r,θ,ϕ)\{-\frac{\hbar^2}{2\mu r^2}[\frac{∂}{∂r}(r^2\frac{∂}{∂r}) + \frac{1}{\text{sin}\theta}\frac{∂}{∂\theta}(\text{sin}\theta\frac{∂}{∂\theta}) + \frac{1}{\text{sin}^2\theta}\frac{∂^2}{∂\phi^2}] - \frac{e^2}{4\pi\epsilon_0r}\}\psi(r,\theta,\phi) = E\psi(r,\theta,\phi)

Solving this equation involves the separation of the variables:

Ψ(r,θ,ϕ)=R(r)P(θ)F(ϕ)\Psi(r,\theta,\phi) = R(r)P(\theta)F(\phi) .


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