Question

Calculate the potential of single electrode
a. Zn2+(aq) (0.1M) / Zn. When Eo= -0.76V.
b. Ag+ (0.01M) / Ag (s) E0 = 0.799

Answer 1

At anode

$Zn\to Zn^{2+}+2e^-$ $.....E_0=0.76 V.................(1)$

at cathode

$Ag^++e^-\to Ag$ .........$E_0=0.799................(2)$

(1)+2$\times$(2)

$Zn+2Ag^+\to Zn^{2+}+2Ag$

$E_{cell}=0.76V +0.799V=1.559 V$