Question

. A human being weighing 75kg consumes 6 million J of sadza per day. Assume the sadza is all glucose and only aerobic respiration occurs to release 2,8 million J/mol of energy stored in ATP. The density of the man is 1000kg/m3.Find the man’s metabolic rate in terms of oxygen moles consumed per m3 of the person per second (mol/ m3/s).

Answer 1

6 million J - 75kg, 1 day

80000000 J - 1000 kg, 1 day

80000000 J - 1 m³, 1 day

926 J - 1 m³, 1 second

0.000331 mol glucose - 1 m³, 1 second

0.00199 mol O₂ - 1 m³, 1 second