What can we deduce from a 17% yield percentage?
Consider a 1.245 g sample of glucose (C6H12O6)
a. calculate moles of glucose in the sample
b. Moles of carbon in 1 mole glucose
c. moles and mass of carbon in the sample
d. glucose molecule in the sample
When [Fe(CO)5] is refluxed with cyclopentadiene, compound A is formed which has the empirical formula C8H6O3Fe and a complicated 1H-NMR spectrum. Compound A readily loses CO to give compound B with two 1H-NMR resonances, one at negative chemical shift (relative intensity 1) and one at around 5 ppm (relative intensity 5). Subsequent heating of B results in the loss of H2 and the formation of compound C. Compound C has a single 1H-NMR resonance and the empirical formula C7H5O2Fe. Compounds A, B, and C all have 18 valence electrons: identify them and explain the observed spectroscopic data
Na[W(η 5 -C5H5)(CO)3] reacts with 3-chloroprop-1-ene to give a solid, A, which has the molecular formula [W(C3H5)(C5H5)(CO)3]. Compound A loses carbon monoxide on exposure to light and forms compound B, which has the formula [W(C3H5)(C5H5)(CO)2]. Treating compound A with hydrogen chloride and then potassium hexafluorophosphate, K+PF6 − , results in the formation of a salt, C. Compound C has the molecular formula [W(C3H6)(C5H5)(CO)3]PF6. Use this information and the 18-electron rule to identify the compounds A, B, and C. Sketch a structure for each, paying particular attention to the hapticity of the hydrocarbons.
2-ethyl-1-propanol structural formula
The reaction of Br2/CCl4 to cyclohexene would produce which compound(s) represented below by structure
Why is less caffeine actually isolated than is suggested by the calculation?
The complex [(FeCp (CO) 2] 2 (Fp2), displays IR carbonyl absorption bands at 1760 and 2000 cm – 1. (A) What is its molecular structure? (B) Fp2 in solution is in equilibrium with a its isomeric structure, which is slightly higher energy What is this structure? (c) How are molecules that have isomeric structures, such as those in question (b) of Fp2, characterized by rapidly reaching equilibrium? What is the consequence? (d) Photolysis of Fp2 leads to the loss of a CO ligand and the new complex obtained exhibits only one IR carbonyl absorption band at 1760 cm – 1. What is the molecular structure of this new complex? e) Heating Fp2 to 180 ° C leads to a quaternary complex that has lost 2 CO per Fp2 complex and exhibits a strong IR absorption band at 1620 cm – 1. What is the structure of the new complex and the number of valence electrons of each the four Fe atoms?
The dimeric compound [(n5-C5Me5)Cr(CO)2]2 (A) follows rule 18e and in the IR spectrum shows absorptions at 1870 cm‒1. Treatment of the compound with excess CO at 1200-450 psi and 175oC for 10 hours gives another dimer compound of chromium (B) which also follows rule 18e and shows infrared absorptions at 1876 cm‒1. Photolysis of compound A by UV radiation leads to dimer compound C together with the release of CO gas. The IR spectrum of compound C shows only one band at 1788 cm‒1 while also showing the same metal-metal bond order as compound A. Propose suitable molecular structures for compounds A, B and C by clearly indicating the Cr την bond order Cr and how to assemble the CO.
Show work Please!
Part A: https://us-static.z-dn.net/files/d02/1520534e314182b69219f5e2ff3390e6.png
Part B: https://us-static.z-dn.net/files/d0e/a5906c429e8e4e42c9e6875e200c985e.png
Part C: https://us-static.z-dn.net/files/d6d/4dd617c2a49a1de568720479cc648feb.png