Question #164889

Consider a 1.245 g sample of glucose (C6H12O6)

a. calculate moles of glucose in the sample

b. Moles of carbon in 1 mole glucose

c. moles and mass of carbon in the sample

d. glucose molecule in the sample


1
Expert's answer
2021-02-22T05:55:57-0500

(a) Molar mass of glucose = C6H12O6=6(12)+12(1)+6(16)=180g/molC_6H_{12}O_6 = 6(12)+12(1)+6(16)= 180 g/mol


(b) Moles of C in 1 mole of glucose C6H12O6=6C_6H_{12}O_6=6 moles


(c) In 180g of sample = 6 moles of carbon

\rightarrow In 1g of sample= 6180\dfrac{6}{180} moles of carbon

So,\rightarrow So, In 1.245g of sample = 6180×1.245=0.0415\dfrac{6}{180}\times1.245 = 0.0415 moles

and mass of carbon in sample = 0.0415×\times 12 = 0.498g


(d) Moles of glucose in sample= 1.245180=6.916×103moles\dfrac{1.245}{180}= 6.916\times 10^{-3}moles

Since, In 1 moles of sample contains 6.023×1023molecules\times10^{23}molecules

So, In 6.916×103moles6.916\times10^{-3} moles or 1.245g of sample of glucose contains 6.91×103×6.023×10236.91\times10^{-3} \times 6.023\times 10^{23}

41.655×1020=4.1655×1021\rightarrow 41.655\times10^{20}=4.1655\times10^{21} particles


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Assignment Expert
24.02.21, 12:28

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Maria
23.02.21, 09:45

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