Answer to Question #90317 in Organic Chemistry for sahil kumar

Question

64 gram methane are mixed with 64 gram of oxygen and burnt,then the mass of carbondioxide obtained is?

Answer 1

The Stoichiometric equation for the reaction is

CH₄ + 2O₂ = CO₂ + 2H₂O

Moles of CH₄  = 64/16 = 4

Moles of O₂ = 64/32 = 2

For every 2 moles of oxygen 1 mole of methane is required thus oxygen is the limiting reactant here.

For 2 moles of oxygen 1 mole of CO₂ is obtained

Thus 2 moles of Oxygen will give 1 mole of carbon dioxide thus giving 44g.