First, the number of moles of glucose that is used in the reaction should be calculated:
n = m/M, where n - number of moles, m - mass, M - molar mass.
n (C6H12O6) = 21 g / 180.2 g/mol = 0.12 mol.
Next, as 678 kcal is released from one mole of glucose, the metabolism of 0.12 mol of glucose results in the release of 0.12 mol × 678 kcal = 81.36 kcal of energy.
Answer: 81.36 kcal
Comments
Leave a comment