Soution: The vibration energy of a molecule is given by E=(v+1/2)hν
where,v= vibrational quantum number, ν=frequency of vibration of the bond,
At 0 K E0=(1/2)hν ,where, E0=zero point energy.
That means even at 0 K temperature bond is vibrating
In order to describe a point in 3d space we need three co-ordinates. So total degree of
freedom =3.So molecules containing N number of atoms =3N,
Among 3N degrees of freedom there are 3 translational degrees of freedom along co-ordinate
axis and 3 rotational degrees of freedom for non-linear molecules,2 for linear molecules.
Since for linear molecules rotation along its bond axis does not change its co-ordinates.
Therefore ,Total number of vibrational degrees of freedom for linear molecules=(3N-5)
And for non-linear molcules=(3N-6)
(i) PF3:Shape-Trigonal pyramidal(Non-linear)
Therefore, Total number of vibrational degrees of freedom=(3×4)-6=6
The number of normal modes of vibration=6
(ii)ClNO:Shape: V shaped(Non-linear)
Therefore ,Total number of vibrational degrees of freedom=(3×3)-6=3
The number of normal modes of vibration=3
(iii) XeF2: Shape: Linear
Therefore ,Total number of vibrational degrees of freedom=(3×3)-5=4
The number of normal modes of vibration=4
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