Answer to Question #288037 in Organic Chemistry for Pranali

Question

A 1.77×10^-1 g sample of HNO₃ and a 5.21 g sample of NO react in a closed 8.91 L container at 470 K, according to the following balanced chemical equation:

2HNO₃(g) + NO(g) → 3NO₂(g) + H₂O(l)

Calculate the P_NO2 (in atm) in the container after the reaction has gone to completion.

Answer 1

Moles of HNO₃ = 1.77 × 10^-1 / 63 =0.003 mol.

Moles of NO = 5.21 / 30 = 0.174 mol.

HNO₃ is limiting reagent .

So, moles of NO₂ formed = 3× 0.003 / 2 mol.

Moles of NO₂ = 0.0045 mol.

From ideal gas equation

P = nRT / V = 0.0045 × 0.0821 × 470 / 8.91

P = 0.02 atm ( APPROX) Answer .