A 7.82 g sample of water is introduced into a 6.46 L flask containing some CO2 gas. The flask is heated to 307.11 °C at which temperature all of the water is converted to the gaseous phase, giving a total pressure in the flask of 12.305 atm. Calculate PH2O (in atm) in the flask at 307.11 °C.
P( h2o)= nRT/V
molar mass of water=18g/mol
total no. of moles of water=(7.82÷18)mol
=0.4344mol
but R=0.0821 L.atm/mol.k
T=(307.11+273) =580.11k
V= 6.46L
Therefore; pressure of water
=(0.4344×0.0821×580.11)÷6.46
= 3.203 atm
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