Answer to Question #230023 in Organic Chemistry for hamza

Question

Which of the following statement is True, based on the following cell diagram

I⁻(aq) I I₂(s) II Br₂(l) I Br⁻(aq)(2.5 Points)

Br₂ will be oxidized in this cell

Br₂ is the oxidizing agent in this cell

I⁻ and I₂ species have the same phase

There is no salt bridge in this cell

I⁻ will be reduced in this cell

Answer 1

$I^-_{(aq)} |I_{2(s)}\ ||\ Br_{2(l)} | Br^-_{(aq)}$

For the cell diagram above, the reaction is;

$2I^-_{(aq)} + Br_{2(l)} \to I_{2(s)}+ 2Br^-_{(aq)}$

from the reaction above, each each iodine loses an electron, so it is the reducing agent. (It is oxidized).

Also, each bromine atom gains an electron and so it is the oxidizing agent. (It is reduced).

$\therefore$ The correct answer is the first option which states that "Br₂ is the oxidizing agent in this cell".