Determine the empirical formula of a compound with the following composition by
mass: 60.0 % C, 8.0 % H and 32.0 % O. If 100 mg of this compound is neutralized
with exactly 10.0 mL of 0.0500 M NaOH in a reaction with a 1:1 stoichiometry,
what is the molecular formula of this compound?
Empirical Formula ="C_7H_6O_3"
Molecular Formula ="C_{14}H_{12}O_{6}"
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