Calcium chloride is used to melt ice on roads.
To determine how much calcium chloride has been used, you take a sample of slush from the road to analyze.
You collect the following data:
Mass of empty container: 54.54 g
Mass of container and sample of slush: 160.65 g
Then, you evaporate the water from the solution and determine the mass of the residue to be 3.29 g. What is the percent by mass of CaCl2 in the slush that was collected?
Given mass of CaCl2=106.11mg=0.10611 g (Since 1g=1000mg)
molar mass of CaCl2=110.08 g/mol
Therefore moles of CaCl2=mass/molar mass=0.10611g/110.08 g/mol=9.64x10^-4 mol.
Let us take volume of solution=1L
therefore molarity of CaCl2=mol/ volume=(9.64x10^-4 mol)
The concentration or molarity of CaCl2=9.64x10^-4 M =0.96 mM ( Since 1M=1000 mM)
We know that 1ppm=1mg in 1L
Here 100 mg in 1L so the concentration of CaCl2=100 ppm. (Parts-per-million).
= 0.00964/0.10611 × 100
=9.08%
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