Answer to Question #219367 in Organic Chemistry for manreet

Question

To determine how much calcium chloride has been used, you take a sample of slush from the road to analyze. 

You collect the following data: 

    Mass of empty container: 54.54 g 

    Mass of container and sample of slush: 160.65 g 

Then, you evaporate the water from the solution and determine the mass of the residue to be 3.29 g. What is the percent by mass of CaCl₂ in the slush that was collected? 

Answer 1

Given mass of CaCO3=100mg=0.1 g (Since 1g=1000mg)

molar mass of CaCO3=100 g/mol

Therefore moles of CaCO3=mass/molar mass=0.1g/100 g/mol=1x10-3 mol.

Let us take volume of solution=1L

therefore molarity of CaCO3=mol/ volume=(1x10-3 mol)/1L=1x10-3 mol/L=1x10-3 M.

The concentration or molarity of CaCO3=1x10-3 M =1 mM ( Since 1M=1000 mM)

We know that 1ppm=1mg in 1L

Here 100 mg in 1L so the concentration of CaCO3=100 ppm. (Parts-per-million).

Here I have taken volume as 1L because you didi not mension anything about volume of solution. If you provide correct value I will recalculate and give you.Thanks an di hope you like it.