State the type of isomerism present in alkene with formula C4H8
Well, the formula C4H8
C4H8 specifies ONE degree of unsaturation; the SATURATED formula would be C4H10
C4H10 the which has TWO structural isomers
Now a degree of saturation specifies an olefinic bond OR a RING junction
So we got two alicyclic structural isomers, i.e. cyclobutane
cyclobutane, and methylcyclopropane
methylcyclopropane to start…
And we could recognize FOUR ACYCLIC OLEFINS: 1-butylene
1-butylene; Z-2-butylene
Z-2-butylene, E-2-butylene
E-2-butylene, and methylpropylene
methylpropylene.
Comments
Leave a comment