Answer to Question #165346 in Organic Chemistry for Haggy

Question

1.09g of a monobromoalkane, A that is immiscible with water was refluxed with excess aqueous sodium hydroxide. The liquid A was dissolved and the resulting solution was neutralized with nitric acid. Excess silver nitrate solution was added and a precipitate of silver bromide was formed. The precipitate was filtered, washed & dried. The precipitate weighed 1.99g.

The filtrate was distilled and a high boiling point liquid B was obtained. b contained 52.2% carbon, 13% hydrogen, and 34.8% oxygen by mass.

C = 12 H = 1 O = 16, Br = 80 Ag = 108

(a) How many moles of A are contained in 1.09g? Explain or show clearly how you arrived at your answer

(b) Determine the molecular formula of B

(c) Name compounds A & B

Answer 1

a) n(A) = 0,01 mol;

m(AgBr) = 1,99 g, n = 0,01 mol

n(Br) = 0,01 mol = n(A)

b) CH₃CH₂OH

c) A - bromoethane

B - ethanol