State which compound A ➡ C shows the least basic character. Explain your choice.
A. CH3CH2CH2NH2
B. CH3CH2CONH2
C. C6H5NH2
D. CH3CH2CO2NH4
Give the reagents and conditions which you would use to
(i) Prepare A from B
(ii) Convert B into ethylamine.
Answer:
Basic: A and C, because they have nitrogen atom with free electron pair.
(i): CH3CH2CONH2 + LiAlH4 = CH3CH2CH2NH2
(ii): CH3CH2CONH2 + NaOBr = CH3CH2NH2
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