Explain why Mo(PMe3)5H2 is a dihydride (contains two separate H ligands), but Mo(CO)3(PR3)2(H2) contains the dihydrogen ligand (Me = methyl, R = isopropyl).
Dihydrogen complex has more sigma donor character than hydride complex. For the first compound PMe3 have no proper pi-acceptor ability. So, the compound is hydride but due to presence of CO, which has higher pi-acceptor characteristics. The second compound get stabilized.
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