Question #163088

Calculate the enthalpy change for the production of one mole of dinitrogen

pentoxide gas from nitrogen gas and oxygen gas. Use the thermochemical equations

a., b., and c. Show all your work. Beside each equation write the changes you are

making to each equation, re-write the equations according to your changes. Your

answer must include a balanced thermochemical equation. Include a potential energy

diagram for your target equation. (5 marks)

a. 2H2(g) + O2(g) ® 2H2O(l) DH° = -572.0 kJ

b. . N2O5(g) + . H2O(l) ® HNO3(l) DH° = -38.5 kJ

c. !

" N2(g) + #

" O2(g) + !

" H2(g) ® HNO3(l) DH° = -174.0 kJ


Expert's answer

N2(g) + 3O2(g) + H2(g) = 2HNO3(l) DH = -174.0 kJ / -H2(g), -0.5O2(g), +H2O(l), +572 kJ/2

N2(g) + 2.5O2(g) + H2O(l) = 2HNO3(l) DH = 112 kJ / -2HNO3(l), -H2O(l), +N2O5(g), +38.5 kJ

N2(g) + 2.5O2(g) = N2O5(g) DH = 150.5 kJ


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