Question

A certain compound has a solubility of 169 g/L in a solvent. If the mixture contains 50 g of 

solute in a 300 cm3

 of solution, is the solution unsaturated? If yes, how many grams of 

solute should be added to make a saturated solution?

Answer 1

If the solubility is 169 g/ L, then 300 cm³ are able to dissolve $\frac{169g\times300mL}{1000mL}=50.7g$ of a solute.

So the solution is unsaturated. There should be 50.7 - 50 = 0.7 g of a solute added to make this solution saturated.

Answer: 0.7 g