There is a typo in the question because there is no compound called 3-methylpropane. Assuming that it was supposed to be 2-methylpropane, there are 2 possible monohalogenated products of this reaction:
1-bromo-2-methylpropane (CH3)2CHCH2Br (1)
2-bromo-2-methylpropane (CH3)3CBr (2)
The product (2) will be major due to the significantly higher reactivity of 3o hydrogen atom compared to 1o hydrogen.
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