As we know that
total mass of solution (mtotal) = weight or mass of H2O (mH2O) + weight or mass of CH3OH (mCH3OH)
total mass of solution (mtotal) = 186 g + 14.8 g
total mass of solution (mtotal) = 200.8 g
Also we know that
mass percent of CH3OH (%) = weight or mass of CH3OH (mCH3OH) 100 / total mass of solution (mtotal)
mass percent of CH3OH (%) = 14.8 g 100 / 200.8 g
mass percent of CH3OH (%) = 1480 / 200.8
mass percent of CH3OH (%) = 7.371 % ( i.e the answer)
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