On heating 1.5 g of a mixture of kclo3 and kcl decreased to 0.12 g. If heating klolo3 creates kcl, calculate the percentage amount of kclo3 in the mixture.
2KClO3 = 2KCl + 3O2
The mass of oxyged released 0.12 g
n(O2)= 0.12/32=0.00375 mol
n(KClO3)=2/3 n(O2) = 0.0025 mol
m(KClO3) = 0.30625 g
w(KClO3) = 0.30625 / 1.5 = 20.42%
Answer: w(KClO3) = 20.42%
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