what voulme of 0.550 M Na2S are needed to react with 15.00mL of 0.217 M Agno3
LET VOLUME IS V ml .
Moles of Na2S = V * 0.550 / 1000 .
Moles Of AgNO3 = 15 * 0.217 / 1000.
Moles Of AgNO3 = 2 * V * 0.550 / 1000 = 15 * 0.217 / 1000 .
So , V = 15 * 0.217 / 2 * 0.550 = 2.9590 ml ...........
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