Solution.
N(O in 1 [Co(H2O)6]Cl2) = 6
N(O in 6×106 [Co(H2O)6Cl2])=6×106×6=36×106N(O \ in \ 6\times 10^6 \ [Co(H2O)6Cl2]) = 6 \times 10^6 \times 6 = 36 \times 10^6N(O in 6×106 [Co(H2O)6Cl2])=6×106×6=36×106
Answer:
N(O in 6×106 [Co(H2O)6Cl2])=36×106N(O \ in \ 6\times 10^6 \ [Co(H2O)6Cl2]) = 36 \times 10^6N(O in 6×106 [Co(H2O)6Cl2])=36×106
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments