Question

The concentration of hydrochloric
acid whose pH is 1.75 is

Answer 1

P^H = -log[H⁺] .

So , [H⁺] = antilog (-P^H).

So , [H⁺] = antilog ( - 1.75 )

So , [ H ⁺] = 1.78 * 10^-2. ANSWER .