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Inorganic Chemistry
define emulsion ?
Inorganic Chemistry
mg+2 is smaller than O-2in size,though both have same electronic configuration ,why?
Inorganic Chemistry
in industrial preparation by changing air to liquid we can produce oxygen by what method?
Inorganic Chemistry
Asolution in a bottle is 1.2 molar concentrated. What volume of it must be diluted with water to obtain
600cm3
of 0.05 molar solution.
600cm3
of 0.05 molar solution.
Inorganic Chemistry
i want to make a solution of sodium chloride of 0.2 moll but the volume has to 50 cm cubed. How would i make the calculations to find out how much of everything is needed?
Inorganic Chemistry
If 1.63 x 10^-4 g of helium dissolves in 100.0 g of waer, what is the concentration in parts per million?
Inorganic Chemistry
When Lead (2) Nitrate reacts with sodium iodide, sodium nitrate and lead (2) iodide are formed. if i start with 25.2 grams of lead (2) nitrate and 15.0 grams of sodium iodide, how many grams of sodium nitrate can be formed?
Inorganic Chemistry
Hi,
the following includes my calculations of how to prepare a hydrochloric acid solution that will only dissolve 10% of a gram of calcium carbonate. Please take a look and tell me if I got it right and if not, tell we were did I went wrong. Thanks in advance!
--------------------------------------…
Number of moles in grams = mass (grams) / molar mass
Number of moles in 0,001 grams CaCO3 = 0.001 / 100 = 0.00001 mole
This will react with double the moles of HCl = 0.00001 x 2 = 0.00002 mole
Converting moles to grams of HCl needed:
HCl gram= molar mass x moles = 36.5 x 0.00002 = 0.00073 gram
0.00073 grams of HCl will react with 0,001 gram CaCO3
0.00073x1179 {density of HCl (22 Baume) in grams}=0.86 milliliter ~ 0.1 milliliter
0.1 milliliter of HCl will react with 0,001 gram CaCO3
0.01 milliliter of HCl will react with 0.0001 gram CaCO3 --------- the 10% per 1 mg
If all the previous calculations considered a 1N HCl solution
Dilution:
Concentration 1 x volume 1 = concentration two x volume 2
the following includes my calculations of how to prepare a hydrochloric acid solution that will only dissolve 10% of a gram of calcium carbonate. Please take a look and tell me if I got it right and if not, tell we were did I went wrong. Thanks in advance!
--------------------------------------…
Number of moles in grams = mass (grams) / molar mass
Number of moles in 0,001 grams CaCO3 = 0.001 / 100 = 0.00001 mole
This will react with double the moles of HCl = 0.00001 x 2 = 0.00002 mole
Converting moles to grams of HCl needed:
HCl gram= molar mass x moles = 36.5 x 0.00002 = 0.00073 gram
0.00073 grams of HCl will react with 0,001 gram CaCO3
0.00073x1179 {density of HCl (22 Baume) in grams}=0.86 milliliter ~ 0.1 milliliter
0.1 milliliter of HCl will react with 0,001 gram CaCO3
0.01 milliliter of HCl will react with 0.0001 gram CaCO3 --------- the 10% per 1 mg
If all the previous calculations considered a 1N HCl solution
Dilution:
Concentration 1 x volume 1 = concentration two x volume 2
Inorganic Chemistry
Predict the mass of hydrogen gas produced when 2.73 g of aluminum reacts in a single replacement reaction with excess sulphuric acid.
Inorganic Chemistry
Aluminum oxide is decomposed using electricity to produce aluminum metal. How many grams of aluminum metal can be produced from 100.0 g of Al2O3?
