Question

The process to remove chromate (3SO2 + 2CrO4 2- + 4H+ = 2 Cr3+ 3SO4 2- + H2O) in a completely mixed reactor has reached equilibrium. If more SO2 was added to the system, how would the chromate in the effluent change?

Answer 1

Answer on Question #53662 – Chemistry – Inorganic Chemistry

Question:

The process to remove chromate (3SO₂ + 2CrO₄²⁻ + 4H⁺ = 2 Cr³⁺ + 3SO₄²⁻ + H₂O) in a completely mixed reactor has reached equilibrium. If more SO₂ was added to the system, how would the chromate in the effluent change?

Answer:

If more SO₂ was added to the system, it will react with CrO₄²⁻ and equilibrium will be shifted to the right (to produce products). It is according to the Chatelier's principle or "The Equilibrium Law".

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