Question #311803

39.8g of a mixture of potassium chloride KCl and potassium trioxochlorate(V), KClO3 were heated to a constant mass. If the residue weighed 28.9g, what was the percentage mass of the potassium chloride in the mixture


1
Expert's answer
2022-03-16T09:08:01-0400

KClO3 + 2KCl → 3KClO

KClO3KClO_3  - x gram

2 moles of Potassium trioxochlorate produces 2 moles of Potassium chloride

x122.5\frac{x}{122.5} Moles will produce same amount of KCl

\\x122.5 mole KCl=x122.5×74.5 g KCl\frac{x}{122.5}\ mole \ KCl=\frac{x}{122.5}\times 74.5\ g\ KCl

write an equation

39.8x+74.5x122.5=28.939.8-x+\frac{74.5x}{122.5}=28.9

x=27.82g

m(KCl)=39.8-27.82=11.98g

thepercentagemass=11.9839.8×100=30.10the percentage mass=\frac{11.98}{39.8}\times100=30.10 %


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