what weight of sodium carbonate must be taken to give 100 cm^3 of a 0.1 M solution?
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Expert's answer
2013-03-29T16:16:27-0400
Theamount of Na2CO3 is n(Na2CO3) = C(M) x V(L) = 0.1 x 0.1 = 0.01mol C -concentration of Na2CO3 solution (M) V - volume of solution (L) [ 100cm^3 = 100 mL = 0.100L ] The mass of Na2CO3 is
m(g) = n(mol) x MW(gmol) Themolar weight of Na2CO3 MW(Na2CO3) = 2 x MW(Na) + MW(C) + 3 x MW(O)
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