Answer to Question #26600 in Inorganic Chemistry for ramya sarvani

Inorganic Chemistry

Question #26600

which of the following is least soluble in water?
A)BaF2 B)SrF2 C)MgF2 D)CaF2

Expert's answer

To know what of the substances is least soluble we have to compare their solubility products.
The least soluble substance has the lowest solubility product.
The dissociation equation is

MF₂ = M²⁺ + 2F^- , where M²⁺ is Ba²⁺, Sr²⁺, Mg²⁺, Ca²⁺

K_sp = [M²⁺][F^-]²

K_sp(BaF₂) = 1.7 x 10^-6
K_sp(SrF₂) = 2.5 x 10^-9
K_sp(MgF₂) = 6.4 x 10^-9
K_sp(CaF₂) = 4.0 x 10^-11

Answer: The least soluble is CaF₂

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21.10.20, 20:50

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08.10.20, 15:58

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08.10.20, 15:58

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