Answer to Question #261893 in Inorganic Chemistry for Moonlight

Question

An aqueous solution of ethanoic acid has a concentration of 10^-2 moldm^-3. The dissociation constant of the acid is 1.7×10^-5 moldm^-3, calculate the following

1)PH of the acid

2) Concentration of H+

3) concentration of OH-

4)Degree of dissociation of the acid

Answer 1

1.7×10^-5 × 10^-2

= 1.7×10^-7

= log 1.7×10^-7

= -6.77

pH = 14+-6.77= 7.23