1. Calculate the number of grams of helium in a 1.00 L balloon at 27.0∘∘C and under 1.00 atmosphere of pressure.
PV= nRT
1×1000=n×8.314×300
1000=2494.2n
n= 0.401
Molar mass of helium=4
= 0.401×4=1.604g
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