Answer to Question #257010 in Inorganic Chemistry for shamsa

Question

3. Chemical stoichiometry 1. Calculate the mass of one atom of lead. 2. Determine the number of moles in each of the following a) 25.0 g of propylene, C3H6 b) 1.0 g of aspirin, C6H4(CO2H)(CO2CH3) 3. Calculate which of the following contains more grams of calcium: 4.6 X 1020 atoms of Calcium or 0.050 mol calcium. 4. Calculate the molarity of a concentrated H2SO4 solution of density 1.84 g/ml and Containing 98.0 % H2SO4 solute by mass.

Answer 1

202 amu is the average weight of a single lead atom. We can also write 202 grams as the weight of an Avogadro's number of lead atoms. If you want the weight in grams of an average lead atom, simply divide the average atomic weight by Avogadro's number.

$m(H2SO4)=0.98×1.84g/mol×1000mL=1803.2gm(H2SO4)=0.98×1.84g/mol×1000mL=1803.2g n(H2SO4)=\dfrac{1803.2g}{98g/mol}=18.4molesn(H2SO4)= 98g/mol 1803.2g ​ =18.4moles c(H2SO4)=\dfrac{18.4moles}{1L}=18.4mol/Lc(H2SO4)= 1L 18.4moles ​ =18.4mol/L$