Calculate the volume, in litres, occupied by 1.0 mol of an ideal gas at STP.
Ideal gas law
pV=nRT
R = 0.08206 L×atm/mol×K
At STP
p = 1 atm
T= 273 K
V=nRTpV=1.0×0.08206×2731=22.4 LV = \frac{nRT}{p} \\ V= \frac{1.0 \times 0.08206 \times 273}{1} = 22.4 \;LV=pnRTV=11.0×0.08206×273=22.4L
Answer: 22.4 L
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