Question

A 110. mL solution of 0.340 M HCl(aq) is mixed with a solution of 330. mL of 0.150 M HNO3(aq). The solution is then diluted to a final volume of 1.00L. How many moles of H+ are present in the final solution?

Answer 1

A 110. mL solution of 0.340 M HCl(aq) is mixed with a solution of 330. mL of 0.150 M HNO3(aq). The solution is then diluted to a final volume of 1.00L. How many moles of H⁺ are present in the final solution?

Solution:

We determined the number moles of H⁺ in both solutions.

The number moles of H⁺ in HCl solution amount to number moles of HCl and equal is: n(H⁺)=0.340·0.110=0.0374 mol.

The number moles of H⁺ in HNO₃ solution also amount to number moles of HNO₃ and equal is: n(H⁺)=0.15·0.330=0.0495 mol.

The concentration of ion H⁺ which form during dissociation of water we disregard, because it is very small value (1·10⁻⁷ mol).

So, in the final solution the number moles of H⁺ are: 0.0374+0.0495=0.0869 mol.

Answer:

The number moles of H⁺ are 0.0869.