Search & Filtering
Write the equation for this reaction, then balance the equation.
B. Calculate the grams of lead(II) iodide that can be produced from 5.00 moles of
potassium iodide.
C. Calculate the grams of lead (II) iodide that can be reproduced from 75.00
grams of potassium iodide
How many grams of solid calcium hydroxide, Ca (OH)2 are required to react with 350 mL of 0.40 mole HCl?
A. If 2.8 moles of Propane reacts with excess Oxygen gas how many grams of CO2 will be formed?
B. How many grams of Oxygen gas will completely react with 3.8 moles of Propane?
C. If 25 g of C3H8 reacts with excess Oxygen, how many moles of water will be formed?
D. If 38 g of water are produced in the reaction, how many moles of CO2 were produced
Calculate the pH and pOH of the following solution and identify each solution as acidic, basic or neutral. (with solutions)
1. [H3O+] = 1.0 x 10-9 M
2. [OH-] = 1.0 x 10-8 M
3. [H3O+] = 0.0010 M
4. [OH-] = 0.010 M
Which statements about dilute sulfuric acid are correct?1. 1. It turns red litmus paper blue. 2. It reacts with magnesium(II) oxide to form magnesium(II) sulfate and water. 3. It reacts with magnesium to form magnesium(II) sulfate and carbon dioxide. 4. Its pH is below pH 7
Identify the conjugate base and conjugate acids of each acid and bases
1. HOCl
4. F-
2. H2PO4-
5. HCO3-
3. H2O
6. H2O
. Calculate the following buffer solution using the Henderson-Hasselbalch equation.
1. Calculate the pH of the buffer solution that contain 0.20 M HOCl (Ka= 4.0 x 10-8) and 0.10 M HCl.
2. What is the pH of a buffer solution that contains 0.50 M CH3CO3H (Ka = 1.8 x 10-5 ) and 0.02 M
H2CO3?
A solution is prepared by dissolving 150 ml of isopropyl alcohol in enough water to produce 1.5 ml of rubbing solution.
A. What is the volume percent of alcohol in the solution?
B. What is the proof of the solution?
Balance the equation below:
1. H₂S + NHO₃ S + NO+ H₂O
Determine which element is oxidized and which element is reduced in reactions below (be sure to include the oxidation state of each):
CO32- + 2H+→CO2 + H2O
