Write the equation for this reaction, then balance the equation.
B. Calculate the grams of lead(II) iodide that can be produced from 5.00 moles of
potassium iodide.
C. Calculate the grams of lead (II) iodide that can be reproduced from 75.00
grams of potassium iodide
2KI = PbI2
The mole ratio is 2 : 1, so, moles of PbI2 = 5.00 / 2 = 2.50 mol
C. Calculate the grams of lead (II) iodide that can be reproduced from 75.00
grams of potassium iodide
moles KI = 75.00 / 166 = 0.45 mol
moles PbI2 = 0.45 / 2 = 0.226 mol
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