Question

Write the equation for this reaction, then balance the equation.

B. Calculate the grams of lead(II) iodide that can be produced from 5.00 moles of

potassium iodide.

C. Calculate the grams of lead (II) iodide that can be reproduced from 75.00

grams of potassium iodide

Answer 1

2KI = PbI₂

The mole ratio is 2 : 1, so, moles of PbI₂ = 5.00 / 2 = 2.50 mol

C. Calculate the grams of lead (II) iodide that can be reproduced from 75.00

grams of potassium iodide

moles KI = 75.00 / 166 = 0.45 mol

moles PbI₂ = 0.45 / 2 = 0.226 mol