Question

If 8.32mg of aniline sample gave 1.11ml of nitrogen at 27°C and 737mmHg. Using Dumas method determine the percentage of nitrogen in the sample

Answer 1

$$PV=nRT$$

Where P- pressure of gas, V - Volume of cylinder, T - temperature, R - constant

n - it is quality of nitrogen, mole,

$$m = nM$$

Where m mass of nitrogen, M - molar mass of nitrogen 28 g/mole

Percentage of nitrogen in sample is

$W = m/ m_{anilin}$

Or

$$W= \frac{PVM}{RTm_{anilin}}$$

W= 0.015 %