As the kinetic energy at any displacement "x" is "\\frac{1}{2}k(A^2-x^2)"
So, "\\frac{1}{2}mv^2=\\frac{1}{2}k(A^2-x^2)"
Hence, "v=0.95697\\frac{m}{sec}"
Kinetic energy at "x=2.80cm"
Kinetic energy"=\\frac{1}{2}k(A^2-x^2)=0.01219J"
Potential energy at "x=2.80cm"
Potential energy"=\\frac{1}{2}kx^2=0.01297J"
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