Let us denote the unknown element by X. We assume it's atomic number to be Z and it's Atomic mass to be A.
"_5B^{11} +_ZX^{A} \\to _6C^{13}+_1H^1"
Now, equating values for Z and A we get;
"11+A=13+1"
"\\implies A=14-11"
"=3"
Similarly; "5+Z=6+1"
"\\implies Z=2"
As, Atomic number is 2, clearly the element is Helium.
And as it's Atomic mass is 3, it has 1 neutron.
Thus the element "_ZX^{A}" can be identified as "_2He^{3}" , which the Helium-3 isotope of Helium.
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