Given at initial conditions : V=10dm3;T=80°C=353KV= 10 dm^3; T =80°C= 353KV=10dm3;T=80°C=353K
As Pressure and number of moles of gas stay constant, from ideal gas law we get;
V/T=constantV/T=constantV/T=constant
Finally V=2.5dm3V=2.5dm^3V=2.5dm3
⟹ Vi/Ti=Vf/Tf\implies V_i/T_i=V_f/T_f⟹Vi/Ti=Vf/Tf
⟹ Tf=(2.5/10)∗353\implies T_f=(2.5/10)*353⟹Tf=(2.5/10)∗353
=78.25K=−194.75°C=78.25 K=-194.75°C=78.25K=−194.75°C
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