Answer to Question #98885 in General Chemistry for Robert Sarberto

Question #98885
A simple of Hydrogen gas occupied a volume of 10dm3 at 80℅. Calculate the new temperature when the gas is cooled and the volume is reduced to 2.5dm3 at constant pressure.
1
Expert's answer
2019-11-19T07:59:33-0500

Given at initial conditions : V=10dm3;T=80°C=353KV= 10 dm^3; T =80°C= 353K

As Pressure and number of moles of gas stay constant, from ideal gas law we get;

V/T=constantV/T=constant

Finally V=2.5dm3V=2.5dm^3

    Vi/Ti=Vf/Tf\implies V_i/T_i=V_f/T_f

    Tf=(2.5/10)353\implies T_f=(2.5/10)*353

=78.25K=194.75°C=78.25 K=-194.75°C


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