"C= \\frac{m}{M \\cdot V}"
"C" - molarity of the solution, mol/l; "m" - mass of the solute, g; "M" - molar mass of the solute, g/mol; "V" - volume of the solution, l.
"M(Al(CH_3COO)_3) \\approx 1 \\cdot 26.98 + 3 \\cdot(2 \\cdot 12.01 + 3 \\cdot 1.01 + 2 \\cdot 16.00) = 204.13 \\; g\/mol"
"C= \\frac{4.31}{204.13 \\cdot 0.1} \\approx 0.21 \\; mol\/l"
Answer: 0.21 mol/l.
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